简答题:设函数ƒ(x)=2x+ln(3x+2)，求ƒ"(0)．

A e B 2 C 1 D 0

A (1+sinx)dx B (1-sinx)dx C sinxdx D -sinxdx

A 5^x-1 B x5^x-1 C 5^xln5 D 5^x

A 1n|2-x|+C B -ln| 2-x|+C C <img src="https://www.beizhujiaoyu.com/uploads/202208/20191017110539_1832.png" width="94" height="26" />  D <img src="https://www.beizhujiaoyu.com/uploads/202208/20191017110543_6803.png" width="79" height="27" /> 

A <img src="https://www.beizhujiaoyu.com/uploads/202208/20191017110551_2261.png" width="78" height="25" />  B ƒ(2x)+C C 2ƒ(2x)+C D <img src="https://www.beizhujiaoyu.com/uploads/202208/20191017110555_3209.png" width="71" height="26" /> 

A 0 B 2 C 2ƒ(-1) D 2ƒ(1)

A 2xy+3+2y B xy+3+2y C 2xy+3 D xy+3

A 柱面 B 球面 C 旋转抛物面 D 椭球面

A 0 B 1 C 2 D 4

A y²=x+C B <img src="https://www.beizhujiaoyu.com/uploads/202208/20191017110621_8140.png" width="82" height="26" />  C y²=Cx D 2y²=x+C